修正任务完成信息的打印逻辑，移除重复输出

sync.py

@@ -98,9 +98,10 @@ async def main():
     for result in results:
         if result is not None and result != 0:
             failed_tasks += 1
+    print(f"{len(results)} tasks completed. {len(results) - failed_tasks} succeed, {failed_tasks} failed.")
     if failed_tasks > 0:
         raise Exception(f"{failed_tasks} tasks failed.")
-    print(f"{len(results)} tasks completed. {len(results) - failed_tasks} succeed, {failed_tasks} failed.")
+    
 
 if __name__ == "__main__":
     asyncio.run(main())